Question

An electric heater of resistance 500Ω is connected to a mains supply for 30 min. If 15A current flows through the filament of the heater, then calculate the heat energy produced in the heater.

Answer 1

hlo. bro here we go please mark as brainliest

We have to calculate the heat energy produced in the heater when the electric heater is of resistance 500 ohms.

And the time of main supply is 30 minutes.

The given Current = I = 5A

Time = 30 minutes.

Converting this time into seconds = 30 × 60 = 1800 seconds.

We know the formula to find heat energy, that is :

H = I²Rt

So ,

H = (5)²×500×1800

= 22500000 J = 2.25 × 10^7

The required heat energy produced in the heater is 2.25 × 10^7 J

plz mark as bliest

Answer 2

$\huge\star{\green{\underline{\mathfrak{Answer :-}}}}$

Given:

• I = 15 A
• R = 500 Ω
• t = 30 min = 1800 sec.

To Find:

• Heat produced = H = I²Rt

Solution:

The Formula of heat produced by the conducted, here, filament of the heater is: I²Rt.

With the help of the given,

➜Heat produced = (15)²×500×1800

➜Heat produced = 225×500×1800

➜Heat produced = 202,500,000 J

➜Heat produced = $\tt{2.025\times {10}^{8}\:J}$

$\rule{200}2$

Joule's law of heating:

The heat produced in a resistor is:

(i) directly proportional to square of current

(ii) directly proportional to resistance

(iii) directly proportional to the time the current flows in the conductor

$\rule{200}4$