Question

In the circuit shown below, calculate the net resistance of the circuit.

Answer 1

The 20 and 5 are in series

hence their net resistance = 20+5 = 25

Similarly

10 and 15 are in series

hence their net resistance is = 10+15 = 25

The combination of both these are in parallel

hence their net resistance is = 25×25/50 = 12.5

Therefore, the net resistance of the circuit is 12.5 ohm

Hope this is helpful to you

Pls mark as brainliest

Follow me and I'll follow you back

Answer 2

1/Rp = 1/R1 + 1/R2 + 1/R3 + 1/R4

= 1/10+1/15+1/20+1/5 = 6/60+4/60+3/60+12/60

= 25/60= 5/12

Rp= 12/5 = 2.4 ohms