Question

An electric heater uses 600kJ of electrical energy in 5 minutes.calculate its power rating.

Answer 1

Given :
E = 600kJ = 600000 J
Time = 5 min = 5×60 = 300 sec
Power = ?

Energy = Power × Time
Power = 600000/300
= 6000/3
= 2000 Watt


hence the power rating is 2000 watt.

hope this helped you ...... !!

Answer 2

Answer:

Given- 600kJ = 600000 J

Time = 5 min = 5×60 = 300 sec

Power = ?

Energy = Power × Time

Power = 600000/300

= 6000/3

= 2000 Watt

hence the power rating is 2000 watt.

hope this helped you ...... !!

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