Question

An electric iron is connected to the mains power supply of 220 V. When the electric iron is adjusted at ‘minimum heating’ it consumes a power of 360 W but at ‘maximum heating’ it takes a power of 840 W. Calculate the current and resistance in each case.

Answer 1

1 case)
Power = P = 360W
Voltage = V = 220v
current = I = ?

P = VI
P/V = 1
360/220 = I
1.63 A = I

2 case)
power = P = 840W
voltage = v = 220v
current = I = ?

P = VI
P/V = I
840/220 = I
3.81 A = I