An electric iron of resistance 20 ohm takes a current of 5a. calculate the heat developed in 30 sec
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Answered by
1
h=I^2 rt
(5)^2 ×20 ×30 = 15000 J
(5)^2 ×20 ×30 = 15000 J
Answered by
6
Given :-
R = 20 Ω
I = 5 A
t = 30 s
H = I^2Rt
= (5)^2×20×30
= 15000 J
= 1.5 × 10^4 J
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