An electric lamp whose resistance is 8 ohms and a conductor of 2 ohms resistance are connected in series to a 5 volt battery . Calculate
a) the total resistance of the circuit
b) the current through the circuit
c) the potential difference across the electric lamp and the conductor
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12th
Physics
Current Electricity
Electrical Resistance & Resistivity
An electric lamp of resista...
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Asked on October 15, 2019 by
Dharan Akavaram
An electric lamp of resistance 20Ω and a conductor of resistance 4Ω re connected to a 6V battery as shown in the circuit Calculate:
(a) The total resistance of the circuit
(b) The current through the circuit
(c)The potential difference across the (i) Electric lamp and
(ii) Conductor, and
(d) Power of the lamp.
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ANSWER
a). the total resistance of the circuit =20Ω+4Ω=24Ω
b). The current through the circuit= current through the bulb= current through the conductor.
The current through the circuit=
the voltage of the battery
voltage applied
.
the current through the circuit =
24
6
amp
The current through the circuit = 0.25amp
c). The potential difference across the lamp and the conductor.
(i) The potential difference across the electrical lamp =0.25×20=5volt
(ii) The potential difference conductor =0.25×4=1 volt
d). Power can be calculated as
current through the lamp
voltage across the lamp
power=
0.25
5
→20W.