Question

an electric oven of 2 KW power rating is operated in a domestic electric circuit 220 volt that has a current rating of 5 ampere What result do you expect explain

Answer 1

power= 2KW or 2000 watts
voltage= 220v
current rating = 5 amperes

We know that, p = v × i
or power = voltage × current
hence 2000= 220× i
2000/220 = i
9.09 Amperes = i

Since the current rating in the circuit is 5 amps and the oven is drawing 9.09 amps of current which is more than the current rating, so it will cause overloading...which can further lead to a short circuit.

Hope it helps!!!

Answer 2

Explanation:

Current drawn by the electric oven can be obtained by the expression,

P = VI

Where,

Current = I

Power of the oven, P = 2 kW = 2000 W

Voltage supplied, V = 220 V

I = 2000/220 V = 9.09 A

Hence, the current drawn by the electric oven is 9.09 A, which exceeds the safe limit of the circuit. Fuse element of the electric fuse will melt and break the circuit.