An electric pole , 16 metre high casts a shadow of 10 metres. Find the height of a tree that casts a shadow of 25 metres under similar condition
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Answer:
40m
Step-by-step explanation:
Given:
Height of pole (Perpendicular) = P₁ = 16m
Length of shadow (Base) = B₁ = 10m
Length of shadow formed by tree (Base) = B₂ = 25m
Height of tree (Perpendicular) = P₂ =??
Since the condition is similar
by using similarity criterion ration of the side will be same
∴P₁/P₂ = B₁/B₂
⇒16/P₂ = 10/25
⇒10P₂ = 16 × 25
⇒ P₂ = 400/10 = 40m
You can also use the proportional method to solve this
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