Question

An electric pole is 10 m high. A steel wire tied to the top of the pole is affixed at a point on the ground to keep the pole upright. If the steel wire makes an angle of 45° with the horizontal through the foot of the pole. Find the length of the steel wire.

Answer 1

✬ Length of wire = 14.14 m ✬

Step-by-step explanation:

Given:

• Height of electric pole is 10 m.
• Steel wire makes an angle of 45° with the horizontal through the foot of the pole.

To Find:

• What is the length of steel wire?

Solution: Let OA be a electric pole of height 10 m and B be a point on the ground and BA = x

• OA = 10 m
• ∠B = 45°

★ In ∆ABO ★

$\small\implies{\sf }$ AO/AB = sin 45° [ Perpendicular/Base ]

$\small\implies{\sf }$ 10/x = 1/√2 [ Value of sin 45° ]

$\small\implies{\sf }$ 10√2 = x [ By cross Multiplication ]

• Value of √2 = 1.414 •

$\small\implies{\sf }$ 10 x 1.414 = x

$\small\implies{\sf }$ 14.14 m = x

Hence, The length of steel wire is x = 14.14 m.

Answer 2

Answer:

Length of wire = 14.14 m ✬

Step-by-step explanation:

Given:

Height of electric pole is 10 m.

Steel wire makes an angle of 45° with the horizontal through the foot of the pole.

To Find:

What is the length of steel wire?

Solution: Let OA be a electric pole of height 10 m and B be a point on the ground and BA = x

OA = 10 m

∠B = 45°

★ In ∆ABO ★

AO/AB = sin 45° [ Perpendicular/Base ]

10/x = 1/√2 [ Value of sin 45° ]

10√2 = x [ By cross Multiplication ]

• Value of √2 = 1.414 •

10 x 1.414 = x

14.14 m = x

Hence, The length of steel wire is x = 14.14 m.