An electric refrigerator rated 400W operates 8 hours day . what is the cost of energy to operate it for the month of january at 30 rupees per kWh
Answers
Answered by
660
Given,
Power = P = 400W = 400/1000 kW = 0.4 kW
Total time for which the refrigerator operated = t = 8 hours x 30 days = 240 h
Since, Energy consumed = P x t E = 0.4 x 240 kWh = 96 kWh
Therefore, total cost required to operate the refrigerator for the month = 96 x 30 = 2880 INR.
Power = P = 400W = 400/1000 kW = 0.4 kW
Total time for which the refrigerator operated = t = 8 hours x 30 days = 240 h
Since, Energy consumed = P x t E = 0.4 x 240 kWh = 96 kWh
Therefore, total cost required to operate the refrigerator for the month = 96 x 30 = 2880 INR.
Answered by
193
Answer:
Power = 400 watt
time = 8 x 30 = 240 hours
energy consumed = power x time = 0.4 x 240 = 96 kwh
total cost required = 96 x 3 = 288 kwh
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