Question

An electric refrigerator rated 400W operates 8 hours day . what is the cost of energy to operate it for the month of january at 30 rupees per kWh

Answer 1

Given,

Power = P = 400W = 400/1000 kW = 0.4 kW

Total time for which the refrigerator operated = t = 8 hours x 30 days = 240 h

Since, Energy consumed = P x t E = 0.4 x 240 kWh = 96 kWh

Therefore, total cost required to operate the refrigerator for the month = 96 x 30 = 2880 INR.

Answer 2

Answer:

Power = 400 watt

time = 8 x 30 = 240 hours

energy consumed = power x time = 0.4 x 240 = 96 kwh

total cost required = 96 x 3 = 288 kwh