An electric train is running at 90 km per hour on stopping Electric Supply to the trains engine that train moving with a constant negative acceleration comes to a halt in 20 sec.
calculate (a) the acceleration of the train and (b) the distance covered by the train during this time
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u = 90km/h or 25m/s
v = 0m/s (Since, it stopped after 20s)
t = 20s
v = u + at
0 = 25 + 20a
a = -25/20
a = -5/4
a = -1.25m/s
2as = v² - u²
2×-1.25×s = 0 - 625
-2.5s = -625
s = 625/2.5
s = 250m
Distance Traveled = 250m
Acceleration = -1.25m/s
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