Question

an electrical contractor purchased a certain amount of wire,1 0% of which was stolen. after using 90% of the remaining wire he had 47.25 m of wire left. how much wire did he purchase?

Answer 1

Suppose he purchased x metres of wire.  10% was stolen, i.e x/10 stolen So, remaining = x- x/10 = y (Suppose)  Now, 90% of y used, i.e 9y/10 So, remaining = y - 9y/10= 47.25m (Given)  => (x - x/10) - 9[(x - x/10)/10] = 47.25M Solve this and you will find that he had purchased 525 metres of wire.

Answer 2

Answer:

The electric contractor purchased $525m$ of wire.

Step-by-step explanation:

Let us suppose the electric contractor purchased $x$ metres of wire.

$10$% of the wire was stolen, i.e. $\frac{x}{10}$ was stolen.

So, remaining amount of wire $= x- \frac{x}{10}$

Let this value be $y$

Now, $90$% of $y$ is used, i.e. $\frac{9}{10}*9$

Now, the remaining is :

$y - \frac{9}{10}y =47.25m$  (This value is given in the question)

$(x - \frac{x}{10} ) - 9[\frac{(x - \frac{x}{10} )}{10} ] = 47.25m$

$\frac{9x}{10}-\frac{81x}{100} =47.25m \\\frac{9x}{100}=47.25m$

$9x=4725m$

$x=\frac{4725}{9} \\x=525m$

Hence, we get that he purchased $525m$ of wire.