Question

An electron in an atom jumps in such a way that its kinetic energy changes from x to , the change in potential energy will be

Answer 1

Assuming a closed system, the total energy is conserved. So we can write qe + pe + KE = qe + PE + ke; where qe = mc^2 is the mass.energy of the electron and that's invariant.

So we can reduce the relationship to pe + KE = PE + KE/4. In which case we have PE - pe = KE - KE/4 = 3/4 KE is the change in potential energy. That is, it increases in value equivalent to 3/4 KE where KE was the initial kinetic energy (your X).

Answer 2

Answer: Here is your answer↓

+ 3x /2

Explanation:

change in K.E.(ΔK.E.) = K.E. final ( K.E. f )  - K.E. initial ( K.E. i )

                          Δ K.E. = X/4 -X

                                     = - 3X/4

  Now, we know that Δ K.E. = - ( Δ P.E. /2 )

                                     -3x /4 = Δ P.E. /2

                                        Δ P.E. =3X /2

Therefore ,the change in potential energy will be Δ P.E. =3X /2