Question

Jai's present age is 3 years more than 3 times the present age of vijay. 3 years from now, jai's age will be 10 more than twice the age of vijay. What is jai's present age in years

Answer 1

Let father = x, son = y

x = 3y + 3

x + 3 = 2(y + 3) + 10
3y + 3 + 3 = 2y + 6 + 10
3y + 6 = 2y + 16
3y - 2y = 16 - 6
y = 10

x = 3y + 3
x = 3 × 10 + 3
x = 30 + 3
x = 33

The present age of the father is 33 years old

Answer 2

$\boxed{GIVEN:-}$

Ratio of their present ages :- 8:5

Ratio of their ages after 6yrs :- 11:8

$\boxed{FIND:-}$

WE HAVE TO FIND THEIR PRESENT AGES....

$\boxed{SOLUTION:-}$

$let, \: their \: present \: ages \: be \: 8x,5x \\ \\ therefore \: after \: 8yrs \: there \: ages \: will \: be \: 8x + 6 ,5x + 6 \\ \\ so,8x + 6 \ratio5x + 6 = 11 \ratio8 \\ \\ \frac{8x + 6}{5x + 6} = \frac{11}{8} \\ cross \: multiply \: it \\ 8(8x + 6) = 11(5x + 6) \\ now \: solve \: it \: for \: value \: of \: x \: we \: have \\ x = 2 \\ so, \: present \: age \: jai = 8x = 8 \times 2 = 16 \\ present \: age \: of \: amy = 5x = 5 \times 2 = 10$