Question

an electron moves in direction opposite to a magnetic field how much magnetic force will it experience​

Answer 1

Answer:

When a charged particle with charge q is moving in an magnetic field B with velocity v it experiences a force F = q (v x B)

Suppose an electron with charge -e and a proton with charge +e move with the same velocity v in the same field B, the forces on them would be

F (electron) = -e (v x B)

F (proton) = +e (v x B)

Obviously the forces are in opposite directions.

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Answer 2

Answer:

The magnitude of the force the electron will experience is zero

Explanation:

• The electromagnetic force results in the magnetic force, which is brought about by the motion of charges.
• The amount of charge, speed, and distance between the two items all affect how much magnetic force there is between them. In each scenario, the relative directions of motion of the charge determine the direction of the force.
• The force experienced by a particle in a magnetic field is F = qvB sinθ
• Where q is the value of the charge, v is the velocity of the particle, B is the magnitude of the magnetic field and θ is the angle between the velocity of the electron and the magnetic field
• Here, the electron moves in a direction opposite to the magnetic field so the angle between the velocity and the magnetic field is 180 degrees
• θ = 180°
• sin θ = sin 180° = 0
• The force experience will be F = qvB sinθ = qvB sin 180° = 0 N

The magnetic force experienced is 0 N.

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