An electron
x moving with the speed of
50 x 10 m/s purpendicular to the magnitio
field of 2.0 a 10 nam calculate the magnetic
Jose acting on
electron
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Answered by
1
Answer:
Given, u=10
3
m/s
a
r
=retardation=−500m/s
2
The time after that the electron stops for a moment is
t=
a
r
v−u
=
a
r
0−u
=
500
10
3
=2s
The same time will be taken by the electron to come back to its initial position
⇒t
′
=t=2s
Hence, the total time taken by the electron in the round trip is
t
tot
=t+t
′
=2+2=4s.
Step-by-step explanation:
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