Question

An element, X has the following isotopic composition.
²⁰⁰X : 90% ; ¹⁹⁹X : 8.0% ; ²⁰²X : 2.0%. The weighed average atomic mass of the naturally occurring element X is close to _______.
(A) 200 amu
(B) 210 amu
(C) 202 amu
(D) 199 amu

Answer 1

Answer:

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The element X has the following isotopic composition:

X

200

=90%,X

199

=8.0%,X

202

=2.0%

The weighted average atomic mass of the naturally occurring X is_________.

Medium

Solution

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Correct option is

B

200 u

Data:-

Element Abundance Atomic Mass

X

200

90% 200

X

199

8.0% 199

X

202

2.0% 202

Formula:-

Average atomic mass= [AtomicmassofX

200

×abundance+

AtomicmassofX

199

×abundance+AtomicmassofX

202

×abundance]/100

=

100

200×90+199×8.0+202×2.0

=

100

18000+1592+404

=199.96≈200u.

Explanation:

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