an eletron starting from rest has a velocity that increases linearly with the time that is v=kt where k=2m/sec2(this is square). The distance travelled in the first 3sec will be
a) 9m
b) 16m
c) 27m
d) 36m
(i need solution pls)
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given acceleration k = 2m/s2 and initial velocity is zero
so using the second equation of motion
s= ut + (1/2)at²
s = 0 + (1/2)×2×3²
s = 9m
so using the second equation of motion
s= ut + (1/2)at²
s = 0 + (1/2)×2×3²
s = 9m
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