show that X + 5 is a factor of the polynomial f x = x cube + x square + 3x + 115
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Answered by
44
If x+5 is a factor of the polynomial, then
f(-5)= 0
F(-5)= (-5)cubed +(-5)squared + 3(-5) + 115
= -125 + 25 - 15 + 115
= -100 -15 +115
= -100 + 100
= 0
Therefore x+5 is a factor of the given polynomial.
f(-5)= 0
F(-5)= (-5)cubed +(-5)squared + 3(-5) + 115
= -125 + 25 - 15 + 115
= -100 -15 +115
= -100 + 100
= 0
Therefore x+5 is a factor of the given polynomial.
Answered by
16
Answer:
If x+5 is a factor of the polynomial, then
f(-5)= 0
F(-5)= (-5)cubed +(-5)squared + 3(-5) + 115
= -125 + 25 - 15 + 115
= -100 -15 +115
= -100 + 100
= 0
Therefore x+5 is a factor of the given polynomial.
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