Math, asked by suryanshumohansingh, 2 months ago

An elevator descends into a mine shaft at the rate 7m/min . if the descends starts from 8 m above the ground level , how long will take to reach -340

Answers

Answered by namangarg128

0

Answer:

2380 mins or 99.1 hour

Step-by-step explanation:

340 under ground floor

340 * 7 = 2380 mins

2380/24 = 99.1 hour

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