Question

an elevator descends into a mine shaft at the rate of 5 m per min.what will be its position after one hour?

Answer 1

1 min 5m
So 60 min = 60 x 5m = 300 m
Pls mark brainliest and thanks for the update

Answer 2

Given the speed is 5m per min.
                time is 1 hr i.e,60 min
                position is given as speed*time
                          =5*60
                           =120m
therefore position after 1 hr will be at 120m