An elevator descends into a mine shaft at the rate of 6 m/min.What will be its position after one hour?If it begins to descend from 20 m above the ground,what will be its position after 45 minutes?
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Answered by
4
6*60=360
it would be 360 metre under ground
if it begins 20 m above ground
after 45minutes it will be in
6*45=270
it starts above 20 metre so
270-20=250
so itf it starts above 20 metre and after 45 minutes it would be 250metre below ground.
hope u like
it would be 360 metre under ground
if it begins 20 m above ground
after 45minutes it will be in
6*45=270
it starts above 20 metre so
270-20=250
so itf it starts above 20 metre and after 45 minutes it would be 250metre below ground.
hope u like
Answered by
0
Answer:
250
Step-by-step explanation:
6*45=270 now subtract the answer with 20
270-20=250
So the answer is 250m/min
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