An elevator in which man is standing in moving upwards with speed 10 m sec if man drops a coin from height 2.45 m it reaches floor after time
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with respect to an observer on ground the coin when relased will freely fall i.e. the initial vel of the coin is 0
using s=1/2gt^2
2.45*2=gt^2
t^2=4.9/9.8=2
t=(1/2)^2
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Answer:
1/root2 sec
Step-by-step explanation:
An observer on ground the coin when relased will freely fall i.e. the initial vel of the coin is = 0
➾ S = 1 / 2gt²
➾ 2.45 × 2 = gt²
➾ t² = 4.9 / 9.8 = 1/2
➾ t = ( 1 / root 2 )
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