Question

An elevator weighing 1000kg attains an upward velocity 4m/s in two seconds with uniform acceleration. the tension in supporting cable will be

Answer 1

Answer:

Tension= F needed

v=u+at

a=4/2=2m/s

T=1000(10+2)

=12000N

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Answer 2

Answer:

The tension in the supporting cable will be 12000 Newtons.

Explanation:

First, let's calculate acceleration. Which is given as,

$\mathrm{a=\frac{v-u}{t} }$        (1)

Where,

a=acceleration of the body

v= final velocity of the body

u=initial velocity of the body

t=time during which the motion occurs

From the question we have,

The mass of the elevator(M)=1000 kg

The upward velocity(v)=4 m/s

The initial velocity(u)=0 m/s

The time during which the motion occurs(t)=2 seconds

By putting the value of "v", "u" and "t" in equation (1) we get;

$\mathrm{a=\frac{4-0}{2} }$

$\mathrm{a=\frac{4}{2} }$

$\mathrm{a=2\ m/s^2}$        (2)

Now, the tension in the string is calculated as,

$\mathrm{T=M(a+g)}$        (3)

g=acceleration due to gravity=10m/s²

Now by inserting the values of "M", "a" and "g" in equation (3) we get;

$\mathrm{T=1000(2+10)}$

$\mathrm{T=1000(12)}$

$\mathrm{T=12000\ N}$

So, the tension in the supporting cable will be 12000 Newtons.

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