Math, asked by hometiwari104, 7 months ago

An employer pays Rs. 30 for each day a worker works, and forfeits Rs. 5 for each day he is idle. At the end of 60 days, a worker gets Rs. 500. For how many days did the worker remain idle?​

Answers

Answered by TheInnocentSoul
5

Answer:

52 days.

Step-by-step explanation:

Suppose the worker remained idle for m days. Then, he worked for (60 - m) days.

30 (60 - m) – 5m = 500

1800 – 25m = 500

25m = 1300

m = 52

So, the worker remained idle for 52 days.

Answered by Anonymous
16

Answer:

Let x be the number of days where employee is working and y be the number of days where employee is sitting idle.

Total number of days = 60

∴ x+y=60...........(1)

He gets 20 rs for each working day and 3 Rs is deducted and total amount he get is 280 Rs

∴ 20x−3y=280......(2)

Multiplyin equation 1 by 3

Hence \:  we \:  get 3x+3y=180...(3)

Adding equation 1 and 3 we get

23x=460</p><p></p><p>x=20</p><p></p><p>

Putting x=20 in equation 1

∴ y=40

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