Math, asked by shilpi2410, 3 months ago

An empty cistern has three pipes A, B and C. A and B can fil it in 5 hours and 6 hours respectively and C can empty it in 2 hours. If these pipes are opened in order at 1 a.m., 2 a.m. and 3 a.m., when
will the cistern be empty again?
(a) 3hr after 3 a.m.
(b) 6 hr after 3 a.m.
(c) 7 1/4hr after 3 a.m.
(d) 8 hr after 3 a.m.

Answers

Answered by rajv08844
0

Step-by-step explanation:

Answer

Let us name the 3 Taps be TA,TB,TC

where TB,TC are emptying pipes and TAis filling Pipe.

Water Supplied by TA in 3 hours=Volume of Tank or V

Water Supplied by TA in 1 Hour=3V 

Similarly, Water Supplied by TB in 4 Hour=V 

Water Supplied by TB in 1 Hour=4V

Using Given Information

⇒3V−CV=−V

Solving,we get

⇒C=43

where C is the Time taken by TC to empty the Full Tank Alone

So, Water Emptied by TC in 43 Hour=

Answer

Let us name the 3 Taps be TA,TB,TC

where TB,TC are emptying pipes and TAis filling Pipe.

Water Supplied by TA in 3 hours=Volume of Tank or V

Water Supplied by TA in 1 Hour=3V 

Similarly, Water Supplied by TB in 4 Hour=V 

Water Supplied by TB in 1 Hour=4V

Using Given Information

⇒3V−CV=−V

Solving,we get

⇒C=43

where C is the Time taken by TC to empty the Full Tank Alone

So, Water Emptied by TC in 43 Hour=V 

Water Emptied by TC in 1 H

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