Question

an engine pumps 400kg water to height of 10m is 40sec find the power of mg efficiency is80 per​

Answer 1

Answer:

800W

m=400kg

H=10m

t=40sec

Input energy =400×g×H=mgn

E

i

=400×10×10=40000J

Energy per sec,E

1

=

40

40000

=1000J/s

Power input =1000J/s

output =1000×80%

800J/s=800W