Physics, asked by cvbn24, 1 year ago

An engineer works in a factory out of station. A car is arrives at the same time as the train. One day thean arrives one hour before usual time. Without waiting for car, he starts walking towards the factory. On the way, he meets the car. The man reaches 10 minutes before the usial time. Find out the time for which the man keep walking


Anonymous: ___k off

Answers

Answered by techtro
1

The time duration to work for the engineers to walk to meet the car for the time reach before half the time for saving the vehicle to travel on the journey is 60-5= 55mins.

The total number of time to be forward for the backward path to the save the car at 10 minutes to obtain at 5 minutes from forward and backward motion. The time for the person will keep just the car backward motion.

Similar questions