Physics, asked by rajeshdahake31ozrrhd, 1 year ago

An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is: If your answer is 6.18 , write 6.18, upto two decimals

Answers

Answered by santy2
0
Let the real side of a square be L then the real are =L×L=L^2
Let length with error=L+0.002 and area is =(L+0.002)^2=L^2+0.004L+0.000004
The error is: The value with error-true value=0.004L+0.000004
The percentage error :((0.004L+0.000004)÷L^2)×100
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