Question

An ideal gas is allowed to expand 5l to 15l once rapidly and once very slowly the magnitude of work done in two processes are W1 and W2 they related as

Answer 1

Assuming that W1 is the work done when the rapid process is carried out and that W2 is the work done when the slow process is carried out, W2 > W1.

During any thermodynamic process, the work done is equal to the area under the P-V graph of the process. Any slow process is reversible in nature, and the maximum area under the graph is achieved when there are infinitesimally small steps in the process. Since W2 is a reversible process, it does maximum work.

Answer 2

Explanation:

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