Question

An insect crawls starting from origin of a x-y plane along a line making angle of 30 degree with the positive x-direction at a speed of 2 cm/s.what is its distance from the x-axis 8 s after it starts crawling?

Answer 1

Answer: $x=8\sqrt{8}cm$

Explanation:

This is kinematics I-D since motion is linear.

We know, two mutually perpendicular directions are completely independent of each other.

Initial x-coordinate of insect, x = 0 .

Angle made by line of motion wrt x-axis,

$\theta = 30\degree$

Speed of insect, u = 2 cm/s

Then,

$x_f=x_i+u*cos(\theta)*t\\ \\=>x_f=0+2*8*\cos(30\degree)\\ \\ =>x_f=16cos(30\degree)\\ \\x_f= 8\sqrt{3}cm$

Answer 2

can't get answer better than above