An iron spherical ball of volume 232848 cm³ has been melted and converted into a cone with the vertical angle of 120° . Find its height and base.
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v= πr²h/3
r = htan60° = √3h
v = π(3h²)h/3 = πh³
given that the volume of material present in the cone = 232848 cm
v = πh³ = 232848
h = ³√(23248/π) ≈ 42.0 cm
r = htan60° = √3h
v = π(3h²)h/3 = πh³
given that the volume of material present in the cone = 232848 cm
v = πh³ = 232848
h = ³√(23248/π) ≈ 42.0 cm
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