The sum of two consecutive even numbers is 38.find the numbers
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Answered by
6
let x = the first even numberlet (x + 2) = the second even number.their
sum must be 38 ∴x + (x + 2) = 38 by simplification we get 2x + 2 =
38 subtracting 2 from each side of the equation we will get 2x = 36
dividing each side of the equation by 2 we will get x = 18 so one number is 18 and another number is 18 + 2 = 20
dividing each side of the equation by 2 we will get x = 18 so one number is 18 and another number is 18 + 2 = 20
Answered by
23
Let the two digit number be x and x+2.
Given that the sum of two consecutive even numbers is 38.
x + x + 2 = 38
2x + 2 = 38
2x = 38 - 2
2x = 36
x = 36/2
x = 18.
If one number is 18 then the other number will be x + 2 = 18 + 2 = 20.
Verification:
(x) + (x + 2) = 18 + 18 + 2
= 18 + 20
= 38.
Therefore the numbers are 18 and 20.
Hope this helps!
Given that the sum of two consecutive even numbers is 38.
x + x + 2 = 38
2x + 2 = 38
2x = 38 - 2
2x = 36
x = 36/2
x = 18.
If one number is 18 then the other number will be x + 2 = 18 + 2 = 20.
Verification:
(x) + (x + 2) = 18 + 18 + 2
= 18 + 20
= 38.
Therefore the numbers are 18 and 20.
Hope this helps!
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Sple(^_^)ndid !
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