Question

An isosceles triangular field's perineter is 250 m and each equal side is 100m find the area of the field.use
$\sqrt{15} = 3.873$

Answer 1

In triangle ABC AB =AC
perimeter = 250
AB+AC+AC=250
100+100+AC=250
AC=50m
Draw altitude AD.
AD=DC
AD=DC=25M
In triangle ABD,
AD^2=AB^2-BD^2
=100^2-25^2
=10000-625
=9375
AD=96.82m
Area =1/2×b×h
=1/2×50×96.82
=2420.5m^2

Answer 2

Answer: Given-a=b=100th and perimeter=250m

Step-by-step explanation:

perimeter=a+b+c

or, 250m=100+100+c

or, 250m= 200+c

or, 50m=c----(1)

semiperimeter =a+b+c/2

after putting values we got 125m as s

using heron's formula 625 underroot

15.