Physics, asked by bhumiraajsinghr6265, 11 months ago

An NaCl molecule is bound due to the electric force between the sodium and the chlorine ions when one electron of sodium is transferred to chlorine. Taking the separation between the ions to be 2.75 × 10−8 cm, find the force of attraction between them. State the assumptions (if any) that you have made.

Answers

Answered by jit71
2

force between the sodium and the chlorine ions when one electron of sodium is transferred to chlorine. Taking the separation between the ions to be 2.75 × 10−8 cm, find the force of attraction between them. State the assumptions (if any) that you have made.

Answered by shilpa85475
22

Explanation:

Step 1:

Let the distance between the ions, i.e. 2,75 ~ 10−8 cm, be the separation between the electron being transferred and the sodium nucleus

q_{1}=-1.6 \times 10^{-19}

q_{2}=1.6 \times 10^{-19}    

q1 is  Net charge on thechlorine ion,  

q2 is Net charge on the sodium ion

Step 2:

Electrostatic force by Coulomb's Law,            

F=\frac{1}{4 \pi \varepsilon_{0}} \frac{q_{1} q_{2}}{r^{2}}

=9 \times 10^{9} \times \frac{1.6 \times 10^{-19} \times 1.6 \times 10^{-19}}{\left(2.75 \times 10^{-10}\right)^{2}}

=9 \times 10^{9} \times \frac{2.56 \times 10^{-38}}{\left(2.75 \times 10^{-10}\right)^{2}}

=9 \times 10^{9} \times \frac{2.56 \times 10^{-38}}{7.56 \times 10^{-20}}

=9 \times 10^{9} \times 0.338 \times 10^{-18}

=3.04 \times 10^{9} \times 10^{-18}

=3.04 \times 10^{-9} \mathrm{N}

Similar questions