An objecobject of height 2 cm is placed at a distance of 30 cm from a convex lens of focal length 10 cm.find the position nature and height of the object.
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1/f = 1/v - 1/u
1/v = 1/f + 1/u
1/v = 1/10 + ( -1/30)
1/v = 1/10 - 1/30
1/v = 2/30
v =15 cm
v/u = hi/ho
15/-30=hi/2
hi=-1/2*2
hi = -1 cm
image is real,inverted and diminished and is formed 15 cm in front of mirror
keep asking
1/v = 1/f + 1/u
1/v = 1/10 + ( -1/30)
1/v = 1/10 - 1/30
1/v = 2/30
v =15 cm
v/u = hi/ho
15/-30=hi/2
hi=-1/2*2
hi = -1 cm
image is real,inverted and diminished and is formed 15 cm in front of mirror
keep asking
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