Question

Two capacitor of 2micro farad and 4micro farad are connected in series and a pd of 1200V is applied across it. The potential difference across 2micro farad will be

Answer 1

Charges on both capacitors in series should be same
Q = CV

Thus

C(1) × V(1) = C(2) × V(2)

But V1 + V2 = 1200
Let V1 = V and V2 = 1200 - V
Therefore

2×V = 4×(1200-V)

6V = 4800
V = 800

Therefore the potential difference across the 2 micro farad capacitor is 800V