Psychology, asked by sagayarajarun, 11 months ago

An object 1.5 cm high when placed in front of a concave mirror, produce a virtual image 3 cm high. If the object is placed at a distance of 6 cm from the pole of the mirror, calculate: a) the position of the image; b) the focal length of the mirror.

Answers

Answered by sagayrajsagaya
6

Answer:

An object 1.5 cm high when placed in front of a concave mirror, produce a virtual image 3 cm high. If the object is placed at a distance of 6 cm from the pole of the mirror, calculate: a) the position of the image; b) the focal length of the mirror.

Explanation:

See in the message

Answered by bunny4917
1

Answer:

Given,

object height h

1

=1.5 cm

real image length h

2

=−3cm

Position of object from the mirror u=−15cm

Mirror magnification formula

m=

h

1

h

2

=−

u

v

1.5

−3

=

−15

−v

v=−30cm

Apply Mirror formula

f

1

=

−30

1

+

−15

1

f=−10cm

Explanation:

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