An object 1.5 cm high when placed in front of a concave mirror, produce a virtual image 3 cm high. If the object is placed at a distance of 6 cm from the pole of the mirror, calculate: a) the position of the image; b) the focal length of the mirror.
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An object 1.5 cm high when placed in front of a concave mirror, produce a virtual image 3 cm high. If the object is placed at a distance of 6 cm from the pole of the mirror, calculate: a) the position of the image; b) the focal length of the mirror.
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Answered by
1
Answer:
Given,
object height h
1
=1.5 cm
real image length h
2
=−3cm
Position of object from the mirror u=−15cm
Mirror magnification formula
m=
h
1
h
2
=−
u
v
1.5
−3
=
−15
−v
v=−30cm
Apply Mirror formula
f
1
=
−30
1
+
−15
1
f=−10cm
Explanation:
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