an object 2 m tall is placed on the principal axis of a convex lens and it's 40cm tall images formed on the screen placed. at a distance of 72cm from the object what is the focal length of the lens
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Answer:
h
1
=2cm
f=5cm
u=−10m=−1000cm
v
1
−
u
1
=
f
1
v
1
−
−1000
1
=
5
1
v
1
=
5
1
−
1000
1
=
1000
200−1
=
1000
199
v=5.02cm
The image is formed 5.02cm behind the convex lens and is real and inverted.
m=
u
v
=
−1000
5.02
=−0.005
m=
h
1
h
2
=−0.005
2
h
2
=−0.005
h
2
=0.01cm
Since the object distance is much greater than the focal length , this example illustrate the case when the object is place.
Explanation:
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