An object 5 cm in length is placed at a distance of 20cm in front of concave mirror of radius of curvature 30cm.Find the position of the image‚ its nature and size.
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Given :
Object distance, u = - 20 cm
Radius of curvature, R = 30 cm
Focal length, f = R/2 = 30/2 = - 15 cm
To Find :
Position of image, it's nature and size?
Solution:
★ Nature of image:
Image is virtual and erect.
Image formed behind the mirror.
⠀━━━━━━━━━━━━━━━━━━━━━━━━━
Size of image,
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Answer:
∴ Refer to the attachment ....
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