An object 50 cm tall is placed on the principal axis of a convex lens. Its 20 cm tall image is formed on the screen placed at a distance of 10 cm from the lens.calculate the focal length of the lens
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Answered by
5
1/f = 1/v -1/u
h1= 50cm
h2=-20cm
v = +10 cm
for convex lens F =+Ve
v/u = h2/h1
10/u = -2/5
u= -25cm
and hence by using lens formula
1/f = 1/10+1/25
1/f= 5/50+2/50
f=+ 50/7
h1= 50cm
h2=-20cm
v = +10 cm
for convex lens F =+Ve
v/u = h2/h1
10/u = -2/5
u= -25cm
and hence by using lens formula
1/f = 1/10+1/25
1/f= 5/50+2/50
f=+ 50/7
Answered by
2
given,
h1=50cm
h2=20cm
V=10cm
h1/h2=V/u
1/f=1/v-1/u
with this formulae you can calculate f.
f=50/7
h1=50cm
h2=20cm
V=10cm
h1/h2=V/u
1/f=1/v-1/u
with this formulae you can calculate f.
f=50/7
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