Physics, asked by sahasrareddym8, 8 months ago

an object a is released from the top of a vertical building of height h at an instant when it has desended x m from the top, another object b is released from y m below the top of that building right from this instant both these objects takes the same amount of time to reach the ground which of the following expressions in the given situations is correct..

a.H=(x+y)^2/4x b.H=(x+y)^2/4y

c.H=(x+y)^2/2x d.H=(x+y)^2/2y​

(please answer guys
its urgent)

Answers

Answered by akkuaugnel
0

Answer:

a.H=(x+y)^2/4x

Explanation:

a.H=(x+y)^2/4x

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