An object dropped from a cliff falls with a constant acceleration of 10 m/s2. Find its speed 5 s after it was dropped.
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Answered by
76
We have,
initial velocity, u = 0 m/s
acceleration. a = 10 m/sā2
final velocity, v = ?
time, t = 5 sec
v = u + at= 0 + (10) Ć 5= 50 m/s
So, after 5 sec, its velocity is 50 m/s.
initial velocity, u = 0 m/s
acceleration. a = 10 m/sā2
final velocity, v = ?
time, t = 5 sec
v = u + at= 0 + (10) Ć 5= 50 m/s
So, after 5 sec, its velocity is 50 m/s.
tanvipragya27:
But we have to find speed
Answered by
24
speed of a object after 5sec is 50m/s
And the speed of object is
speed =displaced/time
=125/5
=25m/s
And the speed of object is
speed =displaced/time
=125/5
=25m/s
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