how much pure alcohol must be added to 400 ml of a 15% solution to make its strength 32%
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15% to 32%
32%- 15%= 17%
17%/100*400
= 68ml
32%- 15%= 17%
17%/100*400
= 68ml
zissu:
the ans is 100 mL
Answered by
2
Hi mate,
Solution :
=> Volume of alcohol in 400 ml solution
➾ 0.15 × 400 ml
=> Volume of alcohol in 400 ml solution
➾ 60 ml
=> Volume of others liquid
➾ 340 ml
=> Let x ml of alcohol is added to make it 32% strong
=> Then, volume of alcohol
➾ 60+x ml
=> Volume of other liquid
➾ 340 ml
=> Volume of solution
➾ 400 + x ml
➾ 0.32 × (400 + x) = 60 + x
➾ 128 + 0.32x = 60 + x
➾ 0.68x = 68
➾ 68x = 6800
➾ x = 100 ml ...
Answer : 100 ml pure alcohol must be added to 400ml of a 15% solution to make it's strength 32%
i hope it helps you
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