An object has an acceleration of 6.0 m/s/s. If the mass of this object were tripled (with no change in its net force), then its new acceleration would be m/s/s
Answers
GIVEN:-
BEFORE CHANGING THE MASS
The acceleration of an object = 6m/s^2
Let the mass of the object = M
Force applied = F
AFTER CHANGING THE MASS
New mass of the object = 3M
Force applied = F
Both the objects have applied with same force.
TO FIND:-
The acceleration of the Object B.
FORMULA TO BE USED:-
FORCE = MASS × ACCELERATION
SOLUTION :-
Let 'a' be the new acceleration.
We know that
Force = Mass × Acceleration
For case 1 :
F = M × 6 = 6M Newton .... (eqn.01)
For Case 2:
F = 3M × a
Putting value of F from equation 01:
6M = 3M × a
=> 6M = 3aM
=> 6(M) = 3a(M)
=> 6 = 3a
=> a = 2m/s^2 (Answer)
Therefore the acceleration of the body is 2m/s^2.
SOME MORE INFORMATION:
Force is a vector quantity which depends on the magnitude, direction, line of action, mass of the body and velocity of the body. Structure of the body also affects the force.
Force is directly proportional to the mass and acceleration. If a body has no acceleration, it's force will be zero. Hence the body moving with uniform velocity has no external force. Example : The gravitational force of Sun and all other planets makes the solar system stable.
Answer: ur required answer ;-
BEFORE CHANGING THE MASS OF OBJECT ;-
the acceleration of the the object = 6m/sec²
let the mass of the object = M
force applied on object = F
AFTER CHANGING THE MASS OF OBJECT ;-
new mass of the object = 3M
force applied = F
As , we know the both object experience same force
FIND = the acceleration of object B
force = mass × acceleration
SOLUTION ;-
let a be the new acceleration .
as , we know force = mass × acceleration
in case 1
F = M × 6 = 6M Newton ............... ( equation 1)
in case 2
F = 3M × a =
now , putting the value of F equation 1
6M = 3aM
6(M)= 3a (M)
6 = 3 a
a = 2 m / sec² .
therefore , the acceleration of the object is 2m/sec²
Explanation: hope this will help u mate , need feedback plz
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