Question

An object is dropped from the top of a building and it hits the ground in 3 seconds . what is the height of the building? (assume the acceleration due to gravity is 32 ft/sec^2)​

Answer 1

Answer:

Height of the building = 144 meter

Step by step explanations :

given that,

An object is dropped from the top of a building and

it hits the ground in 3 seconds

here,

initial velocity of the object = 0 m/s

[It was at rest]

let the final velocity of the object when it hits the ground be v

time taken to hit the ground = 3 seconds

given gravitational acceleration(g)

= -32 ft/s²

now,

we have

initial velocity(u) = 0 m/s²

final velocity(v) = v

time taken(t) = 3 s

gravitational acceleration(g) = -32ft/s²

by the gravitational equation of motion,

h= ut + ½ gt²

where,

h is the height

putting the values,

h = 0(3) + ½ × (-32)(3)(3)

h = -144 m

negation of displacement shows height towards earth.

so,

Height of the building will

= 144 meter