Question

an object is moving up with a velocity V if the velocity of this rocket is suddenly double what will be the ratio of two kinetic energies​

Answer 1

Answer:

1:9

Explanation:

Initial velocity =v, then v =3v (Tripled Velocity)Initial kinetic energy = 21 mv 2

Final kinetic energy (K.E.)= 21mv ′2 = 21 m(3v) 2=9( 21mv2 )

∴ (K.E.) initial

:(K.E.) ffina=21mv 2:9( 21mv 2)=1:9