An object is moving with initial velocity 10m/sec with a constant acceleration -2m/s^2 . Find the total distance covered in 6sec
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3
Answer:
S= 24m
Explanation:
S= ut+ 1/2at^2 6^2= 36
= (10 x 6) + (1/2 x-2 x 36)
= 60 - 36
= 24m
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