Question

An object is moving with initial velocity 10m/sec with a constant acceleration -2m/s^2 . Find the total distance covered in 6sec

Answer 1

Answer:

S= 24m

Explanation:

S= ut+ 1/2at^2         6^2= 36

= (10 x 6) + (1/2 x-2 x 36)

= 60 - 36

= 24m

Answer 2

Answer:

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