Question

an object is moving with uniform acceleration. Its velocity after 5sec is 25 m/s and after 8 sec is 34 m/s. Find the distance travelled by object in 12th sec. Please answer without clicking photo

Answer 1

According to equations of motion, acceleration=v-u/t
                                                                          =34-25/8-5 (duration of this change)
                                                                          =9/3
                                                                          =3 m/s squared
 v=u+at
 u=v-at
 u=34-3*8
 u=10 m/s

distance=ut + 1/2at*t
 10*12 +1/2*3*12*12 
 =336m
all equations based on equations of motion