An object is placed at a dist of 30cm from a concave lens of focal length 15 cm. list four characteristics ( nature postion etc ) of the image formed by lens
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u=-30cm
f=-15cm
1/v=1/f+1/u=-1/15-1/30=-3/30=-1/10
v=-10cm
magnification (m)= v/u=-10/-30
m=1/3=.33
As, the magnification is positive we will get an virtual and erect image.
Image formed will be diminished as m<1
As, v is -ve image formed is at the same side of the lens.
u=-30cm
f=-15cm
1/v=1/f+1/u=-1/15-1/30=-3/30=-1/10
v=-10cm
magnification (m)= v/u=-10/-30
m=1/3=.33
As, the magnification is positive we will get an virtual and erect image.
Image formed will be diminished as m<1
As, v is -ve image formed is at the same side of the lens.
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